You can use -ls as primary (which is slightly different from ls -l) or -exec ls -l {} +. It will however never be completely the same as ls -lR since

http://stackoverflow.com/question...lr-output-to-format-of-find-output

In a find command, what does "{} +" at the end mean? In a find command, what does "{} +" at the end mean? find -L / -samefile /path/to/file -exec ls

http://stackoverflow.com/question...-command-what-does-at-the-end-mean

| cut -d" " -f1 for i in `cat temp` do perm= ls -l $i | cut -d" " -f1 if [ $permission -ne $perm ] then n=`expr $n + 1` fi echo $n done how can i

http://stackoverflow.com/questions/3961109/convert-shell-to-python

from output of ls -l , you can use directly: $ cat files.txt | xargs ls -l | awk '{total += $5} END {print "Total:", total, "bytes"}' Awk interprets "$5"

http://stackoverflow.com/question...olumn-of-numbers-at-the-unix-shell

within single quotes (which would prevent globbing): + dirs=/content/{dev01,dev01} + ls -l '/content/{dev01,dev01}' ls: /content/{dev01,dev01}: No such

http://stackoverflow.com/question...w-to-glob-variables-in-bash-script

directories? What does ls -l <file> give you? it was giving -r-x------ i changed its permission using chmod to -rwxrwxrwx. Even then it is giving the same error.

http://stackoverflow.com/question...l-script-no-such-file-or-directory

about extended attributes. When listing the files using ls -l these are visible with an appended + sign. For example: malbert@dredg:/tmp$ ls -l total 48

http://stackoverflow.com/question...-decides-privileges-allotted-to-it

-perm /g=w -exec ls -lLd {} + I can never keep GNU and FreeBSD find straight. /g=w is correct for GNU find, +g=w is correct for BSD find. Since this is

http://stackoverflow.com/question...ies-writable-by-the-group-in-linux

presence of ACLs can also be seen on ls -l as a + character after the permissions. Rather than changing your umask, you may want to set explicit permissions

http://stackoverflow.com/question...so-that-all-users-can-read-and-wri

>temp permission= ls -al $1 | cut -d" " -f1 for i in `cat temp` do perm= ls -l $i | cut -d" " -f1 if [ $permission -ne $perm ] then n=`expr $n + 1` fi

http://stackoverflow.com/questions/3948532/shell-program-doesnt-work